Question

the third overtone produced by a vibrating string 0.5 m long 1200Hz the speed of propagation of the wave in metre per second is​

Answer 1

given

wavelength w = .5m

frequency f = 1200hz

velocity v = ?

v = w * f

v = .5 * 1200

v = 600m/s

Answer 2

Given that,

Length of the string, l = 0.5 m

Frequency, f = 1200 Hz

To find,

The speed of propagation of the wave.

Solution,

For third overtone,

$f=\dfrac{4v}{2l}$

v is speed of propagation of the wave

$v=\dfrac{2fl}{4}\\\\v=\dfrac{2\times 1200\times 0.5}{4}\\\\v=300\ m/s$

So, the speed of the wave is 300 m/s. Hence, this is the required solution.

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Vibrating string

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