Question

The third proportional between (a^2 - b^2) and (a + b)^2 is:
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Answer 1

Answer:

$\frac{(a+b)(a+b)^{2}}{(a-b)}$

Step-by-step explanation:

Answer 2

Answer:

third proportional to ($a^{2} -b^{2}$) and $(a+b)^{2}$

Answer : $\frac{(a+b) ^{3}}{a-b} = x$

Let Me Know if it's wrong.

Step-by-step explanation:

Let the thrid Proportional be x.

$a^{2}-b^{2} : (a+b)^{2} = (a+b)^{2} : x$

Product of Means = Product of Extremes

$(a+b)^{2}* (a+b)^{2} = a^{2}-b^{1}*x$

$(a+b)^{4} = (a^{2} - b^{2}) * x$

$\frac{(a+b)^{4} }{a+b *a-b } = x$

Most People tends to confuce on the above part a^2-b^ = (a+b)(a-b).

$\frac{(a+b) ^{3}}{a-b} = x$