The third term and fifth term of an A.P. is 5 and 9 respectively. Find the first term and common difference.
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a3 = 5
a5 = 9
since an = a + ( n-1) d
there fore a3 = a + ( 3-1) d
5 = a + 2d >>>>>>> 1 equation
similarly, a5 = a + ( 5-1) d
9 = a + 4d >>>>>>> 2 equation
subtract 1 from 2 equations
4 = 2d
d = 4/2
d= 2
substitute d = 2 in 1st equation
5 = a + 2* 2
5 = a + 4
a = 5 - 4
a = 1
hope it helps you.....!!
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