Question

the third term is 34 and difference is 3 write the first four terms in the Arithmetic sequence

Answer 1

Answer:28,31,34,37....

Step-by-step explanation:

D= 3

A+2D = 34

A=34-2D

A=34-6=28

A1 = 28

A2 = 28+3 = 31

A3=28+2D=34

A4=28+3D=37

@skb

Answer 2

HEY MATE
UR ANSWER

a+2d=34(given)
a+2×3=34(d=3)
a+6=34
a=34-6
a= 28
so,
1st term is a=28
2nd term=28+3=31
3rd term=31+3=34
4th term=34+3=37
then the arithmetic sequence is:-
28,31,34,37...............

HOPE THIS HELPS U