The third term of a geometric progression is 12 and the fifth term is 48 find the sum of the first eleven terms
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Answered by
3
Answer:
The GP is
48, 24, 12, 6, 3, 3/2, 3/4, 3/8, 3/16, 3/32, 3/64
11 th term is 3/64 which could have been also obtained using the formula for the nth term as
An = A1*f^(n-1) where f is ratio of GP which is 1/2 here.
So A11 = 48*(1/2)^10 = 48/1024 = 3/64
Step-by-step explanation:
Hope it will help you,
Answered by
3
Answer:
the answer is
Step-by-step explanation:
3/64 hope it's helpful for you ok .
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