Math, asked by trisharoy1431, 19 days ago

The third term of a geometric progression is 12 and the fifth term is 48 find the sum of the first eleven terms

Answers

Answered by ishvardasmandavi88
3

Answer:

The GP is

48, 24, 12, 6, 3, 3/2, 3/4, 3/8, 3/16, 3/32, 3/64

11 th term is 3/64 which could have been also obtained using the formula for the nth term as

An = A1*f^(n-1) where f is ratio of GP which is 1/2 here.

So A11 = 48*(1/2)^10 = 48/1024 = 3/64

Step-by-step explanation:

Hope it will help you,

Answered by lisa857
3

Answer:

the answer is

Step-by-step explanation:

3/64 hope it's helpful for you ok .

Similar questions