Question

The third term of a gp is 12 and the first term is 48. Find the sum of first 11 terms

Answer 1

Step-by-step explanation:

Let a−d,a,a+d are the three terms of AP

So,

Sum=a−d+a+a+d=48

3a=48

or a=16

And,

a(a−d)=4(a+d)+12

16(16−d)=4(16+d)+12

256−16d=64+4d+12=4d+76

256−76=4d+16d

180=20d

d=9

Which implies:7,16,25

@By Samu_❤__

Answer 2

Answer:

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Step-by-step explanation:

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