Question

The third term of a gp is 18 and its 7th term is 3 5/9 find the 10th term of the gp

Answer 1

Answer:

Step-by-step explanation:

let the first term be a

and common ratio be r

nth term = a r^(n-1)

  third term = a r^2 = 18

  seventh term = ar^6 =35/9

                                   you need to find a r^9

                              you can find a and r by diving the first two equations