The third term of a Gp is 3 and sixth term is 81 find its ninth term
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ar2 = 3 _. 1)
ar5 = 81. _. 2)
from 1 &2 ,
r3 = 27
so , therefore r= 3 , put value of r in eq 1 to obtain the value of a
a= 3/r2
a= 3/ 9= 1/3
therefore a9 = ar8 = 1/3* (3)8
= 3 to the power 7
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