Question

The third term of an A.P is 16 and the 12th term is 79. Find the 41st term​

Answer 1

Answer:

Given,3rd term is (a3)=16

12th term is (a12)=79

Let,the 41st term of the AP is= a41

Now,a3=16=>a+(n-1)d=16

=>a+(3-1)d=16

=>a+2d=16

=>a=16-2d•••••••••(i)

Similarly,a12=79=>a+(n-1)d=79

=>a+(13-1)d=79

=>(16-2d)+12d=79;from eq.n(i)

=>16-2d+12d=79

=>10d=79-16

=>10d=63

=>d=6.3

Now, putting the value of d in eq.n (i) we get

a=16-2(6.3)

=>a=16-12.6

=>a=3.4

Now,the 41st term will be

3.4+(41-1)6.3

=3.4+252

=255.4

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