Question

The third term of an A.P is 16 and the 7th yerm exceeds 5th term by 12 .The first term is

Answer 1

this is ur ans dear
the first term is 4

Answer 2

The third term of the A.P = 16
Given that the 7th term exceeds 5th term by 12.
7th term = a + 6d
5th term = a + 4d
Therefore
a + 6d - (a + 4d) = 12
a + 6d - a - 4d = 12
2d = 12
d = 6

The common difference is 6 
3rd term = 16
a + 2d = 16
a + 2(6) = 16
a + 12 = 16
a = 4

The first term of the A.P = 4

Hope this helps you.