Question

The third term of an A.P is 7 and the seventh term exceeds three times the third term by 2 find the first term ,the common difference

Answer 1

This is the solution for this question and all the best and do well!!!

Answer 2

T3 = a + 2 d = 7
T7 = a + 6 d = 7 * 3 + 2 = 23

T7 - T3 = 4 d = 23-7= 16
d = 4.