Question

The third term of an AP is the 8 and the ninth term of an AP exceeds three times third term by 2.Find the sum of first 19 terms

Answer 1

here u go

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Answer 2

Answer: S19 = 475

A=2

D=3

Step-by-step explanation:

A +2d=8

A+8d=3(a+2d)+2

By solving we get

A+8d=26

By elimination method

We get that d=3

Putting this in the first equation we get that

A+2×(3)=8

A=8-6

A=2

S19=

19÷2(2A+(19-1)d

19÷2(4+18×3)

19÷2(50)

19×25

475