The third term of an arithmetic sequence is 16 the difference between 5th and 7th term is 12 find the sequence
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Answer:
a3=16
a+2d=16
a=16-2d--(i)
a7-a5=12
a+6d-(a+4d)=12
a+6d-a-4d=12
2d=12
d=12/2
d=6
a=16-2d
a=16-2x6
a=16-12
a=4
A.P.=4,10,16
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I hope it helps
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