the third term of GP is 3/2 nad 7th term is 8/27 find the GP
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The required GP is
Step-by-step explanation:
It is given that fourth term of a GP is 2/3 and 7th term is 16/81.
Let the first term of the GP be a and the common ratio is r.
The nth term of a GP is
4th term of the GP is 2/3.
.... (1)
7th term of the GP is 16/81..
.... (2)
Divide equation (2) by equation (1).
The common ratio is 2/3.
Put this value in equation (1).
The first term is 9/4.
The required GP is
Step-by-step explanation:
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