Question

the third term of GP is 4 .the product of first five term is 2556.​

Answer 1

Answer:

Let a be the first term and r the common ratio. Then,

a3=4⟹ar2=4

Therefore,

Product of first five terms = a1a2a3a4a5=a(ar)(ar2)(ar3)(ar4)=a5r10=(ar2)5=45

Step-by-step explanation:

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