The third zero of the polynomial, if the sum and product of whose zeroes are -3 and 2 is:
(a) 7
(6) 7 (c) 14 (d) – 14
Answers
Answered by
19
Step-by-step explanation:
sum of zeros = alpha+beta
=-3
product of zeros= alphabets
=2
Now,
x^2-3x+2
x^2-2x-x+2
X(x-2)-1(X-2)
(x-2)(x-1)
X=2 or X=1
Answered by
10
Answer:
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Step-by-step explanation:
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