The thirteen term of an ap is 4 time its 3rd term if it's 5 term is 16 find the sum of first 10 term
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Given, thirteen term of an ap is 4 time its 3rd term
ie., a+12d=4(a+2d)
a+2d=4a+8d
or a=4d/3 -----I
Also given, 5 term is 16
i.e., a+4d=16
Apply I on this,
we get, (4d/3) + 4d = 16 or d=3
put value of d on I we get, a=4
we have all the data to find the sum of first 10 terms..
Sn = n/2(2a + (n-1)d)
where, n=10; d=3; a=4;
S10 = (10/2)(2*4 +(10-1)*3)
S10=175
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