THE THOUSANDS DIGIT IS HALF OF THE TENS DIGIT-FORM A NINE- DIGIT NUMBER
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Let the number be= ABCD
Here D may be = 2,4,6,or 8
B= 2x2= 4; (or) 4 x 2= 8; {Two times 6 & 8 gives a double digit numbet} . So the possibility of B= 4 or 8.
C=1. This 3- less than .D. So D= 4
Therefore A= (4÷2) =2.
Therefore the number is 2814.
Two Thousand Eight Hundred and Fourteen.
[Note: It is a simple question for IMO- class-5. ]
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