The three angels of a triangle are in the ratio 1 : 2 : 1. Find all the angles of the triangle.
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Answers
Answer:
let the angles of triangle be 1x , 2x and 3x
now , as we know that sum of all angles of a triangle is 180°
then,
1x + 2x + 1x = 180°
4x = 180°
x = 180°/4
x = 45°
1x = 1×45° = 45°
2x = 2×45° = 90°
1x = 1×45 = 45°
All the angles of a triangle are 45° , 90° and 45°
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Answer:
Let the three angles of the given triangle be a,2a and a respectively.
We already know that the sum of three angles of a triangle is 180°.
Now; According to the question--
=> a+2a+a = 180
=> a+2a+a = 180=> 4a = 180
=> a+2a+a = 180=> 4a = 180=> a = 180/4
=> a+2a+a = 180=> 4a = 180=> a = 180/4=> a = 45°
=> a+2a+a = 180=> 4a = 180=> a = 180/4=> a = 45°Now; if a = 45°,then-
=> a+2a+a = 180=> 4a = 180=> a = 180/4=> a = 45°Now; if a = 45°,then-2a = 2×45°
=> a+2a+a = 180=> 4a = 180=> a = 180/4=> a = 45°Now; if a = 45°,then-2a = 2×45° = 90°.
Hence, the three angles of the given triangle are 45°, 90° and 45°.