the three angles in a triangle are in the ratio of 3:4:5. find them
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Answer:
the three angles in a triangle are in the ratio of 3:4:5
(3x, 4x, and 5x)
Step-by-step explanation:
The sum of the interior angles of a triangle will be 180 ° . Therefore, think of the ratios of 3:4:5 as variables followed by "x" (3x, 4x, and 5x).
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RATIO OF ANGLES OF A TRIANGLE = 3:4:5
LET THE COMMON MULTIPLE BE x
1st angle = 3×x = 3x
2nd angle = 4×x = 4x
3rd angle = 5×x = 5x
ATP
1st angle + 2nd angle + 3rd angle = 180⁰ [Sum of all angles of a triangle is 180⁰]
= 3x + 4x + 5x = 180⁰
= 12x = 180⁰
=> x = 180/12
=> x = 15
Therefore,
1st angle = 3x = 3×15 = 45⁰
2nd angle = 4x = 4×15 = 60⁰
3rd angle = 5x = 5×15 = 75⁰
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