the three angles of a quadrilateral are 60 degree,80degree and 120degree.findthe fourth angle
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angle a+b+c+d=360degree
60+80+120+d=360
260+d=360
d=360-260
d=100degree
60+80+120+d=360
260+d=360
d=360-260
d=100degree
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We know that sum of interior angle of quadrilateral is 360°
Here, In quadrilateral ABCD
Ang. A + Ang. B + Ang. C + Ang. D = 360°
60°+ B + 120° + 80°= 360°
Angle B = 360 - 260
Angle B = 100°. Ans
Here, In quadrilateral ABCD
Ang. A + Ang. B + Ang. C + Ang. D = 360°
60°+ B + 120° + 80°= 360°
Angle B = 360 - 260
Angle B = 100°. Ans
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