the three angles of a triangle are in the ratio of 3:4:5 find all the angles of the triangle
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let 1st angle = 3x
2nd angle = 4x
3rd angle = 5x
ATQ,
1st angle + 2nd angle + 3rd angle = 180° [Angle Sum Property]
3x + 4x + 5x = 180°
12x = 180°
x = 180°/12
x = 15°
1st angle = 3x = 3*15= 45°
2nd angle = 4x = 4*15 = 60°
3rd angle = 5x = 5*15 = 75°
2nd angle = 4x
3rd angle = 5x
ATQ,
1st angle + 2nd angle + 3rd angle = 180° [Angle Sum Property]
3x + 4x + 5x = 180°
12x = 180°
x = 180°/12
x = 15°
1st angle = 3x = 3*15= 45°
2nd angle = 4x = 4*15 = 60°
3rd angle = 5x = 5*15 = 75°
Answered by
1
Answer:
3x + 4x + 5x = 180 degrees which means that 12x = 180.
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