Question

The three angles of a triangle are x + 400

, x + 250 and x + 850

. Find

the angles.​

Answer 1

Step-by-step explanation:

given,

∆ABC

let,

∠ABC=X+40

∠BCA=X+25

∠CAB=X+85

w.k.t(we know that)

sum of Angles of ∆ = 180

∠ABC + ∠BCA + ∠CAB =180

(x + 40) + (x + 25) + (x + 85)=180

3X+1500= 180 => 3X= 180-150

3X=30 => X=30/3= 10°

so,

∠ABC=X+40 = 10+40 = 50

∠BCA=X+25 = 10+25 = 35

∠CAB=X+85 = 10+ 85 = 95

therefore angles of ∆ are 50,35,95

type correct question