Question

the three angles of a triangle , one is twice the smallest and another one is thrice the smallest.find the angles

Answer 1

this is only simple method use proper sentences when write answer

Answer 2

Given,

The three angles of a triangle, one is twice the smallest and another one is thrice the smallest.

To Find,

The angles =?

Solution,

We can solve the question as follows:

It is given that the three angles of a triangle out of which one is twice the smallest and another one is thrice the smallest. We have to find all three angles.

Let, the smallest angle be equal to x.

$Smallest\: angle = x$

Then, the second one is twice the smallest.

$Second\: angle = 2x$

The third angle is thrice the smallest.

$Third\: angle = 3x$

Now,

We know that the sum of all the angles in a triangle is always equal to 180 degrees. Hence, the sum of x, 2x, and 3x will be equal to 180.

$x + 2x + 3x = 180^{o}$

$6x = 180^{o}$

$x = \frac{180}{6} = 30^{o}$

Now,

The second angle = $2x = 2*30 = 60^{o}$

The third angle = $3x = 3*30 = 90^{o}$

Hence, the three angles are equal to 30 degrees, 60 degrees, and 90 degrees.