the three angles of a triangle, the second one is one-third of the first and the third angle is 26° more than the first angle. find all the three angles of the triangle
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angles are... 66,22,92
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Let first angle be x°
llnd angle =1/3 × x =(x/3)°
lllrd angle =x+26°
ATQ,
x+x+26+x/3 =180°(angle sum property)
(3x+3x+x+78)/3 =180
7x+78 =180×3
7x =540-78
x =462/7
x =66°
Thus,
lst angle =x° =66°
llnd angle =(x/3)° =22°
lllrd angle =(x+26)° =92°
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llnd angle =1/3 × x =(x/3)°
lllrd angle =x+26°
ATQ,
x+x+26+x/3 =180°(angle sum property)
(3x+3x+x+78)/3 =180
7x+78 =180×3
7x =540-78
x =462/7
x =66°
Thus,
lst angle =x° =66°
llnd angle =(x/3)° =22°
lllrd angle =(x+26)° =92°
HOPE IT WILL HELP U..
PLZ MARK IT AS BRAINLIEST ANSWER..
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