Question

the three angles of triangles, one is thrice the smallest and another is six times the smallest. Find

the value of smallest angle and other angles.​

Answer 1

Step-by-step explanation:

Consider ∠C is the smallest angle among ∠ABC

According to the question

We can write it as

∠A=2∠C and ∠B=3∠C

We know that the sum of all the angles in a triangle is 180

∘

.

So we can write it as

∠A+∠B+∠C=180

∘

By substituting the values

2∠C+3∠C+∠C=180

∘

By addition

6∠C=180

∘

By division

∠C=180/6

∠C=30

∘

Now by substituting the value of ∠C we get

∠A=2∠C=2(30

∘

)=60

∘

∠B=3∠C=3(30

∘

)=90

∘

Therefore, ∠A=60

∘

,∠B=90

∘

and ∠C=30

∘

.