Question

the three consecitive number whose sum is 72​

Answer 1

Solution :

Let 'n' the first of three consecutive numbers.

Let 'n+1' be the second consecutive number.

Let 'n+2' be the third consecutive number.

A.T.Q

(n) + (n+1) + (n+2) = 72

n + n + 1 + n + 2 = 72

3n + 3 = 72

3n = 72 - 3

3n = 69

n = 69/3

n = 23

Therefore, n = 23

n + 1 = 23 + 1 = 24

n + 2 = 23 + 2 = 25 .

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Check:

(n) + (n+1) + (n+2) = 72

23 + 24 + 25 = 72

72 = 72 .

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Answer 2

Solution

Given,

• the three consecutive number whose sum is 72

To find ,

• the three consecutive number

Now ,

• according to the given question ;

Let the three consecutive number be ;

1. n
2. n+1
3. n+2

Now ,

• it will form a equation ;

=> N + N+1 + N+2 = 72

• now solving it we get ;

$= >n + n + 1 + n + 2 = 72$

$= > n + n + n + 1 + 2 = 72$

$= > 3n + 3 = 72$

$= > 3n = 72 - 3$

$= > 3n = 69$

$= > n = \frac{69}{3}$

$= > n = 23$

Now ,

We found the value of N .

then the three consecutive numbers are ;

N = 23

N +1 = 23+1=24

N + 2 = 23+3=25

the consecutive numbers are 23,24,25.

Verification

=> N+N+1+N+2 =72

=> 23+24+25=72

=> 72=72

Hence , verified LHS = RHS !