Question

the three consecutive integers are such that when they are taken in increasing order and multipled by 3 and 5 and 7 respectively. they add up to 124.find these number.​

Answer 1

$\large\red{\tt{\mathfrak{Question:-}}}$

The three consecutive integers are such that when they are taken in increasing order and multipled by 3 and 5 and 7 respectively. they add up to 124.find these number.

$\large\red{\tt{\mathfrak{Answer:-}}}$

Let the three consicutive integer are,

x, x+1, x+2

According to the question,

=> 3x + 5(x+1) + 7(x+2) = 74

=> 3x + 5x+5 + 7x+14 = 124

=> 15x + 19 = 124

=> 15x = 124 - 19

=> 15x = 105

=> x = ${\frac {105}{15}}$

=> x = 7.

then

The first integer= 7.

second integer= 7+1 = 8.

third integer = 7+2 = 9.

Hence, The three numbers are Found.

Thanks.

Answer 2

Answer:

The numbers are 7, 8 and 9

Step-by-step explanation:

Let's take the 3 consecutive numbers as X, X+1, X+2.

Since they are multiplied by 3, 5 and 7 respectively, then the equation will be:

3(X) + 5(X+1) + 7(X+2) = 124

3x + 5x + 5 + 7x + 14x = 124

15x = 124 - 14 - 5

15x = 105

X = 7

Therefore, the numbers are:

X= 7

X+1 = 7+1 = 8

X+2 = 7+2 = 9

Checking

7*3 = 21

8*5 = 40

9*7 = 63

Adding up these numbers will give 124 as the answer.