Question

The three consecutive multiplies of 11 are multiplied
by 2,3 and 4 respectively, they add up to 814.
find the numbers.
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Answer 1

Answer:

77,88,99

Step-by-step explanation:

11x , 11(x+1) , 11(x+2)

11(2x), 11*3(x+1), 11*4(x+2)

22x+33x+33+44x+88=814

99x+121=814

99x=693

x=7

first number=11x=11*7=77

second number=11(x+1)=11(8)=88

third number=11(x+2)=11(9)=99

Answer 2

Answer:

multiples are, 11x, 11(x +1 ), 11(x +2)

when multiplied by, 2, 3, 4

11x x2

33(x+1)

44(x+2)

sum of the above

22x+33x +33+44x+44=814

99x +121=814

99x=814-121 = 693

x = 7

11x, 11(x+l), 11(x+2) becomes

77,88 and 99(multiples of 11)

Nos:

77/11,88/11,99 / 11

= 7,8,9. are Answers