The three consecutive number when taken in order and multiplied by 10,11 and 12 respectively and add upto 695. find the numbers
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hey friend,
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Let the 3 consecutive no. be
(x), (x+1) & (x+2)
B/Q
10(x)+11(x+1)+12(x+2) = 695
=> 10x+11x+11+12x+24 = 695
=> 33x+35 = 695
=> 33x = 695-35
=> 33x = 660
=> x = 660/33
=> x = 220
Therefore,
1st no. = x = 220
2nd no. = x+1 = 220+1 = 221
3rd no. = x+2 = 220+2 = 222
Thus, 3 consecutive no. = 220, 221 & 222
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____________________________
Let the 3 consecutive no. be
(x), (x+1) & (x+2)
B/Q
10(x)+11(x+1)+12(x+2) = 695
=> 10x+11x+11+12x+24 = 695
=> 33x+35 = 695
=> 33x = 695-35
=> 33x = 660
=> x = 660/33
=> x = 220
Therefore,
1st no. = x = 220
2nd no. = x+1 = 220+1 = 221
3rd no. = x+2 = 220+2 = 222
Thus, 3 consecutive no. = 220, 221 & 222
_____________________________
I hope this answer helps you ....
If so then plz mark it brainliest...
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