Question

the three consecutive odd numbers such that the sum of second and third number exceeds the first by 12

Answer 1

Let odd number is (2n+1) " (2n+3) & (2n+5)

(2n+1)+12= (2n+3) + (2n+5)

2n + 13 = 4n + 8

2n = 5

n =5/2

Therefore number is ,

(2n+1) = 2 ×5/2+1=6

(2n+3) = 2×5/2+3=8

& (2n+5) = 2×5/2+5=10