Question

The three consecutive terms of an arithmetic sequence are k, 2k+3, 24 . Find the value of k​

Answer 1

Required Answer:-

Let a,b and c are in arithmetic progression, then the common difference between two consecutive terms will remain same. That means,

➛ b - a = c - b

➛ 2b = a + c

That is, 2(second term) = sum of first term and third term. Hence by using this, let's solve the question above$.$

➛ 2(2k + 3) = k + 24

➛ 4k + 6 = k + 24

➛ 4k - k = 24 - 6

➛ 3k = 18

➛ k = 6

␥ The required value of k is 6.

Answer 2

Answer:

Solution :-

Let a,b and c be in arithmetic progression, then the common difference between two consecutive terms will remain same. That means,

➛ b - a = c - b

➛ 2b = a + c

That is, 2(second term) = sum of first term and third term. Hence by using this, let's solve the question above.

➛ 2(2k + 3) = k + 24

➛ 4k + 6 = k + 24

➛ 4k - k = 24 - 6

➛ 3k = 18

➛ k = 6

Hence, the required value of k is 6.

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