The three-digit number is given. The sum of all different three-digit numbers with the same digits as the given number (including the given number) is 1998 . How many different three-digit numbers satisfy the given property?
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Answered by
9
Answer:
Step-by-step explanation:
Each no. 3, 4, 5 will occur twice at any place. So in all the places it will be 2*(3+4+5) = 24.
In the units place 4 will come and carry is 2. In the tens place it will be 24+2 = 26 so 6 and carry 2. then at hundredth place it will be again 24+2 = 26 so 6 and carry 2.
So the sum will be 2664
Answered by
1
Answer:
Step-by-step explanation:
Step-by-step explanation:
Each no. 3, 4, 5 will occur twice at any place. So in all the places it will be 2*(3+4+5) = 24.
In the units place 4 will come and carry is 2. In the tens place it will be 24+2 = 26 so 6 and carry 2. then at hundredth place it will be again 24+2 = 26 so 6 and carry 2.
So the sum will be 1988
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