Question

The three-digit number is given. The sum of all different three-digit numbers with the same digits as the given number (including the given number) is 1998 . How many different three-digit numbers satisfy the given property? please give me step by step solution​

Answer 1

Answer:

Step-by-step explanation:

Each no. 3, 4, 5 will occur twice at any place. So in all the places it will be 2*(3+4+5) = 24.

In the units place 4 will come and carry is 2. In the tens place it will be 24+2 = 26 so 6 and carry 2. then at hundredth place it will be again 24+2 = 26 so 6 and carry 2.

So the sum will be 2664