the three digit number XYZ is divisible by 9 if....
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As it is divisible by 9 then x+2+y+1+z must be divisible by 9. So x+y+z+3 must be divisible by 9. Then x+y+z must be divisible by 3 and must not be divisible by 9. So x+y+z should be equals to 6,15,24,33.
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