The three digit possible natural number using each of digit 9 0 and 8 ones are
Answers
Answer:
HOW MANY DIGIT IS VISIBLE BY 9?
Step-by-step explanation:
Three digit numbers start from 100 and end at 999.
Smallest three-digit natural number which is divisible by 9 is 108.
Now from 108, if you repeatedly add 9 with 108(until you reach 999), then the result will be a three-digit natural number divisible by 9.
That is first you get 108+ 9=117
Then 117+ 9 = 126
Then 126 + 9 = 135
……
until you reach 999.
Logic is that, as 108 is divisible by 9 then (108+9×n) will also be divisible by 9.
Where n is the number of times you add 9 with 108.
Now, question is …. maximum how many times we can add 9 with 108 this way?
At last, 108 + 9×n will be equal to 999(as 999 is the largest 3-digit number divisible by 9).
108+ 9×n = 999
=> 9×n = 891
=> n = 891/9 = 99.
So, maximum 99 times you can add 9 with 108.
Thus there are 99 three-digit natural number after 108 which are multiple of 9.
Therefore
Including 108 there are 99+1= 100 number of 3-digit numbers which are divisible by 9.
Answer is 100.
Answer:
Answer is =
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