Physics, asked by musiclover7388, 1 year ago

The three initial and final position of man on the x-axis are given as
1)(-3m,7m)
2)(7m,-3m)
3)(-7m,3m)
Which pair gives negative displacement
a)1&2
b)2&3
c)1&3
d)1,2&3

Answers

Answered by sohailabbas
23

Answer:

pair 2) (7m,-3m)

gives negative displacement

Explanation:

Given points are

1)(-3m,7m)  

2)(7m,-3m)

3)(-7m,3m)

we know that on x-axis points can be written as (x1,x2)

Displacement=x2-x1

for pair 1

x2-x1=7m-(-3m)=7m+3m=10m

we can clearly see that displacement is positive

for pair 2

x2-x1=-3m-7m= -10m

we can clearly see that displacement is negative

for pair 3

x2-x1=3m-(-7m)=3m+7m=10m

we can clearly see that displacement is positive.

Answered by EhsaanGhaazi
0

The pair 2)(7m,-3m) gives the negative displacement.

We know that,

Displacement = Final position - Initial position

​i.e, Δx = x_2 - x_1

Then,

(i) Δx = 7m−(−3m) = 4m

(ii) Δx = −3m−7m = −10m

(iii) Δx = 3m−(−7m) = 10m

Thus, only the pair 2)(7m,-3m) gives the negative displacement.

#SPJ2

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