The three no.are in the ratio 3:7:9. if 5 is subtracted from the second ,the resulting numbers form an A.P .
find the original numbers.
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Step-by-step explanation:
let the constant of propotionality be x, then the 3 nos. are 3x, 7x, 9x
according to ur qestion 3x, 7x-5, 9x form an AP.
=> there must be a common difference (d)
(7x-5)-3x = d = 9x -(7x -5)
4x-5 =2x +5
2x = 10
x = 5
therefore the 3 nos. are
3*5=15, 7*5=35 and 9*5=45
ans. 15,35,45
hope it helpz u..!! :)
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