the three numbers are in the ratio 2:3:5 the sum of the cubes is 34560 find the numbers
Answers
Answered by
1
Hey dear!!
Here is yr answer.....
Given,
The three nos. are in the ratio 2:3:5
Sum of the nos. = 34560
Sum of the ratios 2:3:5 = 2+3+5 = 10
First no. = 2/10 × 34560 = 6912
Second no. = 3/10 × 34560 = 10368
Third no. = 5/10 × 34560 = 17280
Therefore, the nos. are ---- 6912 , 10368 and 17280
Hope it hlpz....
Here is yr answer.....
Given,
The three nos. are in the ratio 2:3:5
Sum of the nos. = 34560
Sum of the ratios 2:3:5 = 2+3+5 = 10
First no. = 2/10 × 34560 = 6912
Second no. = 3/10 × 34560 = 10368
Third no. = 5/10 × 34560 = 17280
Therefore, the nos. are ---- 6912 , 10368 and 17280
Hope it hlpz....
Answered by
0
Hey
Here is your answer,
Ratio of three numbers = 2:3:5
Let the three numbers be 2x, 3x, and 5x.
Given,
Sum of their cubes = 34560
(2x)^3 + (3x)^3 +(5x)^3 =34560
Solving this ,
We get,
x=6
Now, we know that the value of x is 6.
We are going to find the numbers.
2x = 2×6 = 12
3x = 3×6 = 18
5x = 5×6 = 30
Hence, the numbers are 12, 18, and 30.
Hope it helps you!
Here is your answer,
Ratio of three numbers = 2:3:5
Let the three numbers be 2x, 3x, and 5x.
Given,
Sum of their cubes = 34560
(2x)^3 + (3x)^3 +(5x)^3 =34560
Solving this ,
We get,
x=6
Now, we know that the value of x is 6.
We are going to find the numbers.
2x = 2×6 = 12
3x = 3×6 = 18
5x = 5×6 = 30
Hence, the numbers are 12, 18, and 30.
Hope it helps you!
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