Question

the three numbers are in the ratio 3 ratio 4 ratio 5 the sum of their cube is 0.0017 28 find the numbers

Answer 1

let ratio be x =3x,4x,5x
A/q
or,3x+4x+5x=0.001728
or,12x=0.001728
or,x=0.000144

Answer 2

The three numbers are in the ratio 3 : 4 : 5

let the1st number be=3x

2nd number be=4x

3rd number be=5x

the sum of their cube is 0.0017 28

ATP

[3x]^3+[4x]^3+[5x]^3=0.001728

27x^3+64x^3+125x^3=0.001728

216x^3=1728/1000000  [finding the cubes on both sides we get]

[6x]^3=[12/100]^3

[6x]=[1/50]  [taking the cube root of boath sides]

6x=1/50

1st number be=3x=3*1/50 =0.06 ANS

2nd number be=4x=4*1/50=0.08 ANS

3rd number be=5x=5*1/50 =0.1  ANS