The three numbers are in the ratio 4:5:6. If the sum of the largest and
the smallest number is equal to the sum of the second largest number
and 55. Find the numbers.
Answers
Provided: The three numbers are in the ratio 4:5:6. & sum of the largest and smallest number is equal to the sum of 2nd largest no. and 55.
Need to find: The three respective numbers.
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❍ Let's say, that the three numbers which are in the ratio be 4x, 5x and 6x.
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- Given condition, if sum of the largest and smallest number is equal to the sum of 2nd largest no. and 55.
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Therefore,
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- First no. 4x, 4(11) = 44
- Second no. 5x, 5(11) = 55
- Third no. 6x = 6(11) = 66
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Answer:
Given :-
- The three numbers are in the ratio of 4 : 5 : 6.
- The sum of the largest and the smallest number is equal to the sum of the second largest number and 55.
To Find :-
- What are the numbers.
Solution :-
Let,
First number = 4x
Second number = 5x
Third number = 6x
According to the question,
Hence, the required numbers are :
First number :
Second number :
Third number :
The numbers are 44 , 55 and 66 respectively.
VERIFICATION :-
By putting x = 11 we get,
Hence, Verified.
#Learn more :
3 Sum of three numbers which are in the ratio 3:4:5 is 60. What is the sum of their squares?
(A)1970
(B)1430
(C)1250
(D)1760
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