Question

The three numbers in



a.P. Whose sum is 18 and product is 192 are _______.

Answer 1

Answer:

4 , 6, 8

Step-by-step explanation:

sum of 3 nos.; 4+6+8=18

product given = 192

soln-> 4*6*8 = 192.

Hope U Understand this answer clearly ....

Answer 2

Three numbers are 4, 6 and 8.

Step-by-step explanation:

Let the three numbers in A.P. be (a - d), (a), (a + d)

So, given that there sum is 18.

A.T.Q

(a - d) + a + (a + d) = 18

a - d + a + a + d = 18

3a = 18

a = 18/3

a = 6

__________________________

Now, their product

(a - d) * (a) * (a + d) = 192

(Put Value of a)

(6 - d) * 6 * (6 + d) = 192

(6 - d)(6 + d) = 192/6

36 - d² = 32

-d² = -32 - 36

-d² = -4

d = √4

d = ± 2

____________________

Putting d as 2.

(6 - 2) = 4

(6) = 6

(6 + 2) = 8

____________________

Putting d as -2

(6 - (-2)) = 8

(6) = 6

(6 + (-2)) = 4