Physics, asked by akashchourasia2892, 4 months ago

The three resistances of 2 ohm, and 5 ohm are connected in series.If the potential across the combination is 10 V the current passing through the circuit is .............................

(2 Points)

A)1 A

B)0.1 A

C)10 A

D)100 A

Answers

Answered by Ekaro
37

Correct Question :

The three resistances of 2 ohm, 3 ohm and 5 ohm are connected in series.If the potential across the combination is 10 V the current passing through the circuit is ____.

Solution :

❒ Here three resistances of 2Ω, 3Ω and 5Ω are connected in series with a battery of 10V.

First of all we need to find equivalent resistance of the series connection.

➨ R = R₁ + R₂ + R₃

➨ R = 2 + 3 + 5

R = 10 Ω

As per ohm's law, current flow in the circuit is directly proportional to the applied potential difference.

Mathematically, V = I R

» V denotes voltage

» I denotes current

» R denotes resistance

By substituting the given values;

➠ V = I × R

➠ 10 = I × 10

➠ I = 10/10

I = 1 A

(A) is the correct answer!

Answered by Anonymous
3

Answer:

Correct Question :

The three resistances of 2 ohm, 3 ohm and 5 ohm are connected in series.If the potential across the combination is 10 V the current passing through the circuit is ____.

Solution :

❒ Here three resistances of 2Ω, 3Ω and 5Ω are connected in series with a battery of 10V.

First of all we need to find equivalent resistance of the series connection.

➨ R = R₁ + R₂ + R₃

➨ R = 2 + 3 + 5

➨ R = 10 Ω

As per ohm's law, current flow in the circuit is directly proportional to the applied potential difference..

Mathematically, V = I R

» V denotes voltage

» I denotes current

» R denotes resistance

By substituting the given values;

➠ V = I × R

➠ 10 = I × 10

➠ I = 10/10

➠ I = 1 A

∴ (A) is the correct answer!

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