Question

The three sides of a triangle are consecutive integers and their perimeter is 72 cm. find the measure of each side of triangle​

Answer 1

Answer:

let the three sides be x , x+1 and x+2 respectively perimeter of a triangle = sum of all sides

72 = x +x+1 + x + 2

72 = 3x + 3

72/3= 3x

24 = 3x

x = 24/3

x= 8

therefore the sides are

x =8

x+1=9

x+2=10

Answer 2

Answer:

Let 1 side of triangle be x

Then,

x+x+1x+2=72

3x+3=72

3x=72-3

3x=69

x=69÷3

x=23

1 side of a triangle=23

Therefore,x+x+1+x+2

23

23+1=24

23+2=25

3 sides of a triangle are

23,24 and 25 respectively