Question

the three sides of a triangle are consecutive integers and their perimeter is 72. Find the measure of each side of triangle??
Please solve my problem​

Answer 1

Answer:

23,24 and 25.

Step-by-step explanation:

As the three sides of a triangle are consecutive integers.

Then the sides of a triangle be x,x+1,x+2

Perimeter of the triangle is 72

Then the equation will be

x+x+1+x+2=72

3x+3 =72

3x =69

x =23

Putting the value of x we get

x = 23

x + 1 = 24

x + 2 = 25

The measure of each side of triangle is 23,24 and 25.

Answer 2

Answer:

I side of triangle = 23

II side of triangle = 24

III side of triangle = 25

Step-by-step explanation:

Let,

I side of triangle = x

II side of triangle = x + 1

III side of triangle = x + 2

As we know,

Perimeter of triangle = sum of three sides

So,

P = a + b + c

⇒ a + b + c = 72

⇒ x + x + 1 + x + 2 = 72

⇒ 3x + 3 = 72

⇒ 3x = 72 - 3

⇒ 3x = 69

⇒ x = 69 / 3

⇒ x = 23

★ Value of x + 1

⇒ 23 + 1

⇒ 24

★ Value of x + 2

⇒ 23 + 2

⇒ 25

Therefore,

I side of triangle = 23

II side of triangle = 24

III side of triangle = 25