Math, asked by samreennahal, 4 months ago

The three sides of a triangle are consecutive integers and the perimeter
is 72. Find the measure of each side of the triangle.

Answers

Answered by nitinadityaraj
0

Answer:

first side = 23

second side = 23 + 1 = 24

third side = 23 + 2 = 25

Step-by-step explanation:

x + x + 1 + x + 2 = 72

3x + 3 = 72

72 - 3 = 3x

69 = 3x

x = 23

first side = 23

second side = 23 + 1

third side = 23 + 2

Answered by nightread
0

Answer:

1st side = x

2nd side = (x + 1)

3rd side = (x + 2)

Perimeter = 72

x + (x + 1) + (x + 2) = 72

x + x + 1 + x + 2 = 72

x + x + x + 1 + 2 = 72

3x + 3 = 72

3x = 72 - 3

3x = 69

x = 69 ÷ 3

x = 23

Hence, 1st side = 23

2nd side = x + 1

= 23 + 1

= 24

3rd side = x + 2

= 23 + 2

= 25

Hope it helps

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