Question

The three sides of a triangle are n, 3n−6, and 4n−11. If the perimeter of the triangle is 39 inches, what is the length of each side?

Answer 1

$\huge\sf\underline{Solution:}$


Sides of triangle= n, 3n-6,4n-11

Perimeter= 39 inches

Side+Side+Side= Perimeter

or, n + (3n-6)+(4n-11)=39

or, n+3n-6+4n-11=39

or, 8n=39+6+11

or, 8n=56

or, n=56/8

or, n=7

Therefore, length of each side:-

n= 7 inches

3n-6=(3×7-6) inches
=15 inches

4n-11=(4×8-11)
=21 inches

Answer 2

HELLO DEAR FRIEND

given sides of a triangle = n, 3n−6, and 4n−11.

Perimeter = 39

We know that,

sum of sides = perimeter of triangle.

n + 3n−6 + 4n−11 = 39

8n - 17 bm= 39

8n = 39 + 17

8n = 56

$\large{x = \frac{ \large{56}}{ \large{8}} }$

$\large{ \boxed{8}}$

given sides = n, 3n−6, and 4n−11.

= 8 , 3(8) - 6 , 4(8) - 11

8 , 18 , 21

so, the length of each sides of a triangle =

$\huge \: { \bf{\boxed{ \boxed{8} \: \: \boxed{18} \: \:\boxed{21}}}}$

HOPE IT HELPS