Question

The three sides of the triangle ABC are equal as shown. find the angles x and y​

Answer 1

Answer:

Step-by-step explanation:

Triangle ABC is an equilateral triangle, sum of a triangle =180°

Therefore, 180÷3= 60°

Given, angleA= angle B=angle C. X=60°. Angle C= z=60°. Angle A = 90-60=30, 60-30=30 therefore, angle x=30°

Answer 2

$\:\: \underline{\underline{\bf{\large\mathfrak{~~solution~~}}}}$

now ....it is a equilateral triangle as all the sides are equal.

let ,the side is ="a" unit

now ...the median(AD) is

$= \sqrt{a {}^{2} - ( \frac{a}{2}) {}^{2} } \\ = \sqrt{ \frac{ 3 a {}^{2} }{4} } \\ = \frac{ \sqrt{3} }{2} a$

now ...

$= > \sin(x) = \frac{AD}{AB} \\ = > \sin(x) = \frac{ \frac{ \sqrt{3} a}{2} }{a} \\ = > \sin(x) = \frac{ \sqrt{3} }{2} \\ = > \sin(x) = \sin(60) \\ = > x = 60$

therefore

y+X+90°=180°

=>y+X=90°

=>y=90°-60°

=>y=30°