the three sold frequency why zero for a metal is 7.0 into 10 to the power 14 calculate the kinetic energy of electron emitted when a radiation of frequency y equals to 1.0 into 10 to 15 hit the metal
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K.E ( kinetic energy ) = h ( f - f₀ )
h ----- > plank's constant.
f₀ ------> Threshold frequency.
f --------> Frequency .
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h = 6.626 × 10⁻³⁴
f₀ = 7× 10¹⁴ Hz
f = 1 × 10¹⁵ Hz
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K.E = (6.626 ×10⁻³⁴ ) ₓ [ (1 × 10¹⁵) - (7× 10¹⁴)].
= 1.987 × 10⁻¹⁹ J
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