Question

The three solutions of the equation f(x) = 0 are -2, 0, and 3. Therefore, the three solutions of the equation f(x - 2) = 0 ​

Answer 1

Answer:

f(x) = (x-1)-sin(4x) e-0.5 x = 0 (xz-x1) [Hint. The update formula for secant and Regula-Falsi methods is x,-x1-h ren). Only the logic of picking the next two guesses is different. Use radians in the calculations.] (a) Show the first four iterates (i.e. x1, x2, X3, x4) starting with the initial guesses of x0.8 and x20.9 with the secant method. (b) Show the first four iterates (i.e. x1,x2,x3, x4) starting with the initial guesses of x0.8 and 20.9 with the regula-falsi method. (c) Rewrite the above equation as a fixed point iteration in the form x 1 + sin(4x) e-0.5. Generate three iterates using x,-0.3 g(x), where g(x)- (d) If the actual solution is x = 0.84506,